Câu 2: Trang 31 - sgk toán lớp 5

Gửi bởi: Nguyễn Thị Ngọc Vào 22 tháng 4 2019 lúc 14:55:29

Tính:

$\frac{3}{4}+\frac{2}{3}+\frac{5}{12}$

$\frac{7}{8}-\frac{7}{16}-\frac{11}{32}$

$\frac{3}{2}\times \frac{2}{7}\times \frac{5}{6}$

$\frac{15}{16}\div \frac{3}{8}\times \frac{3}{4}$

$\frac{3}{4}+\frac{2}{3}+\frac{5}{12}=\frac{9}{12}+\frac{8}{12}+\frac{5}{12}=\frac{22}{12}$

$\frac{7}{8}-\frac{7}{16}-\frac{11}{32}=\frac{28}{32}-\frac{14}{32}-\frac{11}{32}=\frac{3}{32}$

$\frac{3}{2}\times \frac{2}{7}\times \frac{5}{6}=\frac{3\times 2\times 5}{5\times 7\times 6}= \frac{30}{210}$

$\frac{15}{16}\div \frac{3}{8}\times \frac{3}{4}=\frac{15\times 8\times 3}{16\times 3\times 4}= \frac{360}{192}=\frac{15}{8}$